document.write( "Question 671744:  If csc x = 5,  90 degrees < x < 180 degrees.\r
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document.write( "a. sin (x/2) =?\r
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document.write( "b. cos (x/2) =?\r
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document.write( "c. tan (x/2) =?\r
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document.write( "So far I have sin = 1/5, but I have no idea what to do after.
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| Algebra.Com's Answer #417749 by lwsshak3(11628)      You can put this solution on YOUR website! If csc x = 5, 90 degrees < x < 180 degrees. \n" ); document.write( "a. sin (x/2) =? \n" ); document.write( "b. cos (x/2) =? \n" ); document.write( "c. tan (x/2) =? \n" ); document.write( "find exact values \n" ); document.write( "** \n" ); document.write( "sinx=1/cscx=1/5=opp side/hypotenuse \n" ); document.write( "adj side=√(5^2-1^2)=√(25-1)=√24 \n" ); document.write( "cosx=-√24/5 \n" ); document.write( "tanx=opp side/adj side=-1/√24 \n" ); document.write( "you are working with a reference angle in quadrant II where sin is>0, cos<0, and tan<0 \n" ); document.write( ".. \n" ); document.write( "Identities: \n" ); document.write( "sin(x/2)=±√[(1-cosx)/2] \n" ); document.write( "=√[(1+√24/5)/2] \n" ); document.write( "=√[(5+√24)/5)/2] \n" ); document.write( "sin(x/2)=√[(5+√24)/10] \n" ); document.write( ".. \n" ); document.write( "cos (x/2) =±√[(1+cosx)/2] \n" ); document.write( "=√[(1-√24/5)/2] \n" ); document.write( "=√[(5-√24/5)/2] \n" ); document.write( "=√[(5-√24)/10] \n" ); document.write( ".. \n" ); document.write( "tan (x/2)=sinx/(1+cosx) \n" ); document.write( "=[(1/5)/(1-√24/5)] \n" ); document.write( "=1/(5-√24) \n" ); document.write( " |