document.write( "Question 671876: What is a cubic polynomial function in standard form with zeros 1, –2, and 2?
\n" ); document.write( "Which one out of the following,
\n" ); document.write( "1) function= x3 + x2 – 3x + 4
\n" ); document.write( "2) function= x3 + x2 – 4x – 2
\n" ); document.write( "3) function= x3 + x2 + 4x + 4
\n" ); document.write( "4) function= x3 – x2 – 4x + 4
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Algebra.Com's Answer #417685 by jim_thompson5910(35256)\"\" \"About 
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x = 1, x = -2 or x = 2\r
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\n" ); document.write( "\n" ); document.write( "x - 1 = 0, x + 2 = 0 or x - 2 = 0\r
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\n" ); document.write( "\n" ); document.write( "(x - 1)(x + 2)(x - 2) = 0\r
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\n" ); document.write( "\n" ); document.write( "(x - 1)(x^2 - 4) = 0\r
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\n" ); document.write( "\n" ); document.write( "x(x^2 - 4) - 1(x^2 - 4) = 0\r
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\n" ); document.write( "\n" ); document.write( "x^3 - 4x - x^2 + 4 = 0\r
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\n" ); document.write( "\n" ); document.write( "x^3 - x^2 - 4x + 4 = 0\r
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\n" ); document.write( "\n" ); document.write( "So the function is f(x) = x^3 - x^2 - 4x + 4, which is choice 4)
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