document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=671805>Question 671805</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Wanda paddles six miles downstream in 1 hour and her friend minnie rowing 1 mph faster goes upstream 6 miles in 2 hours. Find the speed of the current and the girls speeds/rate<BR>\n" );
document.write( "I can solve it with whole numbers, but now my teacher tells me the answer should be a number rounded to the hundredths.<BR>\n" );
document.write( "I tried <BR>\n" );
document.write( "b-c=3mph<BR>\n" );
document.write( "b+c=6mph<BR>\n" );
document.write( "2b=9mph<BR>\n" );
document.write( "b=4.5mph<BR>\n" );
document.write( "so 4.5mph+c=6mph<BR>\n" );
document.write( "    c=1.33mph<BR>\n" );
document.write( "but plugging that into b+c=6mph comes out to 4.5+1.33=5.83<BR>\n" );
document.write( "Maybe that is close enough?<BR>\n" );
document.write( "I also tried this formula from the text<BR>\n" );
document.write( "Total time=distance upstream(d1)/      + (d2)distance downstream/<BR>\n" );
document.write( "           speed of boat upstreamm      speed of boat downstream\r<BR>\n" );
document.write( "\n" );
document.write( "or t=  d1/r-c  +  d2/r+c  where r=rate and c=current<BR>\n" );
document.write( "but that was not working either.<BR>\n" );
document.write( "Any advice on this would be tremendous.<BR>\n" );
document.write( "Thanks\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #417668 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=417668\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Wanda paddles six miles downstream in 1 hour and her friend minnie rowing 1 mph faster goes upstream 6 miles in 2 hours. Find the speed of the current and the girls speeds/rate<BR>\n" );
document.write( "I can solve it with whole numbers, but now my teacher tells me the answer should be a number rounded to the hundredths.<BR>\n" );
document.write( "I tried <BR>\n" );
document.write( "b-c=3mph<BR>\n" );
document.write( "b+c=6mph<BR>\n" );
document.write( "2b=9mph<BR>\n" );
document.write( "b=4.5mph<BR>\n" );
document.write( "so 4.5mph+c=6mph<BR>\n" );
document.write( "    c=1.33mph<BR>\n" );
document.write( "but plugging that into b+c=6mph comes out to 4.5+1.33=5.83<BR>\n" );
document.write( "Maybe that is close enough?<BR>\n" );
document.write( "I also tried this formula from the text<BR>\n" );
document.write( "Total time=distance upstream(d1)/      + (d2)distance downstream/<BR>\n" );
document.write( "           speed of boat upstreamm      speed of boat downstream\r<BR>\n" );
document.write( "\n" );
document.write( "or t=  d1/r-c  +  d2/r+c  where r=rate and c=current<BR>\n" );
document.write( "but that was not working either.<BR>\n" );
document.write( "Any advice on this would be tremendous.<BR>\n" );
document.write( "Thanks\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Let Wanda’s speed be S, and current’s speed, C<BR>\n" );
document.write( "Since Wanda paddled 6 miles downstream in 1 hour, then total speed = 6 mph (<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6%2F1 ALIGN=MIDDLE  ALT=\"6%2F1\"   DISABLED_style= \"max-width:90%; height:auto;\" >). Adding the current's speed to hers, we can say that: S + C = 6 ------ eq (i)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Since Minnie paddled 6 miles upstream in 2 hours, then total speed = 3 mph (<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6%2F2 ALIGN=MIDDLE  ALT=\"6%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >). Subtracting the current's speed from hers, we can say that: S - C = 2 ---- eq (ii)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "S + C = 6 ----- eq (i)<BR>\n" );
document.write( "S - C = 2 ----- eq (ii)<BR>\n" );
document.write( "2S = 8 ---- Adding eqs (ii) & (i)<BR>\n" );
document.write( "S, or Wanda’s speed = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8%2F2 ALIGN=MIDDLE  ALT=\"8%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%284%29 ALIGN=MIDDLE  ALT=\"highlight_green%284%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > mph\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Minnie’s speed = S + 1, or 4 + 1, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%285%29 ALIGN=MIDDLE  ALT=\"highlight_green%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > mph\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "4 + C = 6 ------ Substituting 4 for S in eq (i)<BR>\n" );
document.write( "C, or current’s speed = 6 – 4, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%282%29 ALIGN=MIDDLE  ALT=\"highlight_green%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > mph\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );