document.write( "Question 670975: An equation is given. (Enter your answers as a comma-separated list. Round terms to three decimal places where appropriate. If there is no solution, enter NO SOLUTION.)
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document.write( "− 2/sqr3 cos 3θ = 1 \n" );
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Algebra.Com's Answer #417569 by lwsshak3(11628) ![]() You can put this solution on YOUR website! An equation is given. (Enter your answers as a comma-separated list. Round terms to three decimal places where appropriate. If there is no solution, enter NO SOLUTION.) \n" ); document.write( "− 2/sqr3 cos 3θ = 1 \n" ); document.write( "** \n" ); document.write( "[0,2π] \n" ); document.write( "cos 3θ=1/(-2/√3)=-√3/2 \n" ); document.write( "3θ=7π/6 and 11π/6 in quadrants III and IV where cos<0 \n" ); document.write( "θ=7π/18 and 11π/18 \n" ); document.write( " |