document.write( "Question 670975: An equation is given. (Enter your answers as a comma-separated list. Round terms to three decimal places where appropriate. If there is no solution, enter NO SOLUTION.)
\n" ); document.write( "− 2/sqr3 cos 3θ = 1
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Algebra.Com's Answer #417569 by lwsshak3(11628)\"\" \"About 
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An equation is given. (Enter your answers as a comma-separated list. Round terms to three decimal places where appropriate. If there is no solution, enter NO SOLUTION.)
\n" ); document.write( "− 2/sqr3 cos 3θ = 1
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\n" ); document.write( "[0,2π]
\n" ); document.write( "cos 3θ=1/(-2/√3)=-√3/2
\n" ); document.write( "3θ=7π/6 and 11π/6 in quadrants III and IV where cos<0
\n" ); document.write( "θ=7π/18 and 11π/18
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