document.write( "Question 671650: verify by changing the left side only:
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document.write( "sinX/1-cotX - cosx/tanX-1 = sinX + cosX \n" );
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Algebra.Com's Answer #417545 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! verify by changing the left side only: \n" ); document.write( "sinX/1-cotX - cosx/tanX-1 = sinX + cosX \n" ); document.write( "** \n" ); document.write( "(sin/1-cot)-(cos/tan-1) \n" ); document.write( "[sin/(1-cos/sin)]-[cos/(sin/cos-1)] \n" ); document.write( "[sin/(sin-cos)/sin)]-[cos/(sin-cos)/cos] \n" ); document.write( "[sin^2/(sin-cos)]-[cos^2/(sin-cos)] \n" ); document.write( "(sin^2-cos^2)/(sin-cos) \n" ); document.write( "(sin+cos)(sin-cos)/(sin-cos) \n" ); document.write( "sinx+cosx \n" ); document.write( " \n" ); document.write( " |