document.write( "Question 671717: An father is twice his sons age , twelve years ago he was four times his sons age .What are the ages of the father and son? \n" ); document.write( "

Algebra.Com's Answer #417522 by mananth(16946) $\"\"$ $\"About$

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let father be x
\n" ); document.write( "son be y
\n" ); document.write( "x=2y\r
\n" ); document.write( "\n" ); document.write( "12 years ago
\n" ); document.write( "father's age = x-12
\n" ); document.write( "son's age y-12\r
\n" ); document.write( "\n" ); document.write( "(x-12) = 4(y-12)\r
\n" ); document.write( "\n" ); document.write( "but x=2y\r
\n" ); document.write( "\n" ); document.write( "(2y-12)=4(y-12)\r
\n" ); document.write( "\n" ); document.write( "2y-12=4y-48
\n" ); document.write( "2y-4y=-48+12
\n" ); document.write( "-2y=-36
\n" ); document.write( "y=-36/-2
\n" ); document.write( "y=18 son's age\r
\n" ); document.write( "\n" ); document.write( "x= 2y
\n" ); document.write( "x=36 father's age\r
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