document.write( "Question 60769This question is from textbook alegbra concepts and applications
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document.write( ": Find the domain of y = x+ 3 if the range is (-1,1,3,5)\r
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document.write( "PLEASE HELP! \n" );
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Algebra.Com's Answer #41749 by mszlmb(115)![]() ![]() You can put this solution on YOUR website! Just as domain are the x values, range are the y values. To null out any confusion, \"y\" is the same as \"f(x)\" if that is the notation you are using. \r \n" ); document.write( "\n" ); document.write( "For each range value -1, 1, 3, and 5, we will have an x value. To find the corresponding x to each y value, we just plug in the range for y, one at a time \r \n" ); document.write( "\n" ); document.write( "-1: \n" ); document.write( "y=x+3 replace y with -1 \n" ); document.write( "-1=x+3 minus three on both sides \n" ); document.write( "-4=x there, so for the range value -1, the domain is -4. \r \n" ); document.write( "\n" ); document.write( "1: \n" ); document.write( "1=x+3 minus three \n" ); document.write( "-2=x .: [the sign for 'therefore'] for the range 1, the domain is -2. \r \n" ); document.write( "\n" ); document.write( "3: \n" ); document.write( "3=x+3 minus three both sides \n" ); document.write( "0=x so for range 3 domain is 0. \r \n" ); document.write( "\n" ); document.write( "5: \n" ); document.write( "5=x+3 minus three both sides \n" ); document.write( "2=x so for range 5 domain is 2 \r \n" ); document.write( "\n" ); document.write( "We just put them in order. We were given range {-1,1,3,5} so our domain should be {X when y=-1, X when y=1, X when y=3, X when y=5} in that order. X when y=-1 was -4, X when y=1 was -2, X when y was 3 was 1, X when y was 5 was 2. Our answer is thus {-4,-2,1,2}. \r \n" ); document.write( "\n" ); document.write( "For further help or questions email or im. \n" ); document.write( " |