document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=671285>Question 671285</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Twice a first number plus a second number is 42, and the first number minus the second number is-6 . Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #417457 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=417457\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the two numbers be a & b<BR>\n" );
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document.write( "Write an equation for each statement, then use elimination<BR>\n" );
document.write( "\"Twice a first number plus a second number is 42,\"<BR>\n" );
document.write( " and \"the first number minus the second number is-6\"<BR>\n" );
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document.write( "2a + b = 42<BR>\n" );
document.write( " a - b = -6<BR>\n" );
document.write( "--------------adding eliminates b, find a<BR>\n" );
document.write( "3a = 36<BR>\n" );
document.write( "a = 36/3<BR>\n" );
document.write( "a = 12<BR>\n" );
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document.write( "I'll let you find b </SPAN>\n" );
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