document.write( "Question 671454: Joyce combines 9 atoms of hydrogen and 3 atoms of nitrogen to make 3 molecules of ammonia.
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document.write( "write a direct variation equation which relates atoms of hydrogen to atoms of nitrogen.
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document.write( "How many nitrogen atoms does Joyce need to form ammonia molecules using 51 hydrogen atoms?
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document.write( "Graph the direct variation with nitrogen along the x-axis \n" );
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Algebra.Com's Answer #417436 by stanbon(75887) ![]() You can put this solution on YOUR website! Joyce combines 9 atoms of hydrogen and 3 atoms of nitrogen to make 3 molecules of ammonia. \n" ); document.write( "write a direct variation equation which relates atoms of hydrogen to atoms of nitrogen. \n" ); document.write( "a = k*h*n \n" ); document.write( "------ \n" ); document.write( "Solve for \"k\" using \"9 atoms of hydrogen and 3 atoms of nitrogen make 3 ammonia\". \n" ); document.write( "3 = k*9*3 \n" ); document.write( "k = (1/9) \n" ); document.write( "-------- \n" ); document.write( "Equation: \n" ); document.write( "a = (1/9)*h*n \n" ); document.write( "----------------------- \n" ); document.write( "How many nitrogen atoms does Joyce need to form ammonia molecules using 51 hydrogen atoms? \n" ); document.write( "a = (1/9)*51*n \n" ); document.write( "# of nitrogen = (9/51)(# of ammonia atoms) \n" ); document.write( "-------------------- \n" ); document.write( "Graph y = (51/9)x \n" ); document.write( " \n" ); document.write( "----------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "===================== \n" ); document.write( " |