document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=52590>Question 52590</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 0.6(x-50)=18-0.3(40-10x) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41735 by </B><A HREF=/tutors/aboutme.mpl?userid=terbear1963><B>terbear1963(43)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=terbear1963><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41735\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.6(x-50)=18-0.3(40-10x) ---> 10(0.6x-30)=(18-12+3x)10 ---> 6x-300=180-120+30x ---> 6x-300=60+30x ---> -360=24x ---> x=-15   I hope this helps you out!? Your math friend, Terry   cats7051@yahoo.com </SPAN>\n" );
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