document.write( "Question 671136: Mahmoud runs to a marker and back in 15 minutes. His speed on the way to the market is 5m/s and his speed on the way back is 4m/s. Find the distance to the marker. \n" ); document.write( "
Algebra.Com's Answer #417273 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let distance to market be x m\r \n" ); document.write( "\n" ); document.write( "Total time = 15 minutes= 900 seconds\r \n" ); document.write( "\n" ); document.write( "Time going to market + time returnibg = total time \n" ); document.write( "t=d/r\r \n" ); document.write( "\n" ); document.write( "x/4+x/5 =900\r \n" ); document.write( "\n" ); document.write( "Lcd = 20\r \n" ); document.write( "\n" ); document.write( "Multiply equation by 20\r \n" ); document.write( "\n" ); document.write( "5x+4x= 900*20 \n" ); document.write( "9x= 900*20 \n" ); document.write( "x= 900*20/9 \n" ); document.write( "x= 2000 meters\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |