document.write( "Question 671032: how do i solve sqrt(2x) + 2 > 4
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document.write( "I then got sqrt(2x) > 2
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document.write( " then squared both sides 2x > 4
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document.write( " x > 2\r
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document.write( "then i did 2x >= 0
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document.write( " x >= 0 \r
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document.write( " 0 <= x > 2 is this right? or where did I go wrong.\r
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document.write( "Thanks in Advance
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document.write( "
Algebra.Com's Answer #417264 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "how do i solve sqrt(2x) + 2 > 4 \n" ); document.write( " -2 -2 \n" ); document.write( "I then got sqrt(2x) > 2 \n" ); document.write( " then squared both sides 2x > 4 \n" ); document.write( " x > 2\r \n" ); document.write( "\n" ); document.write( "then i did 2x >= 0 \n" ); document.write( " x >= 0 \r \n" ); document.write( "\n" ); document.write( " 0 <= x > 2 is this right? or where did I go wrong.\r \n" ); document.write( "\n" ); document.write( "Thanks in Advance\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "That's it, and it only!!! You then do the check to make sure that your answer is correct.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |