document.write( "Question 671032: how do i solve sqrt(2x) + 2 > 4
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\n" ); document.write( "I then got sqrt(2x) > 2
\n" ); document.write( " then squared both sides 2x > 4
\n" ); document.write( " x > 2\r
\n" ); document.write( "\n" ); document.write( "then i did 2x >= 0
\n" ); document.write( " x >= 0 \r
\n" ); document.write( "\n" ); document.write( " 0 <= x > 2 is this right? or where did I go wrong.\r
\n" ); document.write( "\n" ); document.write( "Thanks in Advance
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Algebra.Com's Answer #417264 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "how do i solve sqrt(2x) + 2 > 4
\n" ); document.write( " -2 -2
\n" ); document.write( "I then got sqrt(2x) > 2
\n" ); document.write( " then squared both sides 2x > 4
\n" ); document.write( " x > 2\r
\n" ); document.write( "\n" ); document.write( "then i did 2x >= 0
\n" ); document.write( " x >= 0 \r
\n" ); document.write( "\n" ); document.write( " 0 <= x > 2 is this right? or where did I go wrong.\r
\n" ); document.write( "\n" ); document.write( "Thanks in Advance\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"highlight_green%28x+%3E+2%29\"\r
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\n" ); document.write( "\n" ); document.write( "That's it, and it only!!! You then do the check to make sure that your answer is correct.\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com \r
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