document.write( "Question 671032: how do i solve sqrt(2x) + 2 > 4
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document.write( " -2 -2
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document.write( "I then got sqrt(2x) > 2
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document.write( " then squared both sides 2x > 4
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document.write( " x > 2\r
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document.write( "then i did 2x >= 0
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document.write( " x >= 0 \r
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document.write( " 0 <= x > 2 is this right? or where did I go wrong.\r
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document.write( "Thanks in Advance
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document.write( "
Algebra.Com's Answer #417263 by ReadingBoosters(3246)![]() ![]() ![]() You can put this solution on YOUR website! Most importantly, \n" ); document.write( "x cannont be >=0 to achieve greater than 4 \n" ); document.write( "... \n" ); document.write( " \n" ); document.write( "0 + 2 = 2 which is not > 4 \n" ); document.write( "... \n" ); document.write( "The first answer takes care of the second. \n" ); document.write( "x cannot be greater than 2 yet equal to or greater than zero. \n" ); document.write( "... \n" ); document.write( "The first answer exludes 1, while the second answer includes it. \n" ); document.write( "... \n" ); document.write( "You first answer was enough to solve the inequality \n" ); document.write( "x > 2 \n" ); document.write( "... \n" ); document.write( "So long as x is > 2, it will always be > 0 \n" ); document.write( "..................... \n" ); document.write( "Delighted to help. \n" ); document.write( "-Reading Boosters \n" ); document.write( "Wanting for others what we want for ourselves. \n" ); document.write( "www.MyHomeworkAnswers.com \n" ); document.write( " \n" ); document.write( " |