document.write( "Question 671032: how do i solve sqrt(2x) + 2 > 4
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\n" ); document.write( "I then got sqrt(2x) > 2
\n" ); document.write( " then squared both sides 2x > 4
\n" ); document.write( " x > 2\r
\n" ); document.write( "\n" ); document.write( "then i did 2x >= 0
\n" ); document.write( " x >= 0 \r
\n" ); document.write( "\n" ); document.write( " 0 <= x > 2 is this right? or where did I go wrong.\r
\n" ); document.write( "\n" ); document.write( "Thanks in Advance
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Algebra.Com's Answer #417263 by ReadingBoosters(3246)\"\" \"About 
You can put this solution on YOUR website!
Most importantly,
\n" ); document.write( "x cannont be >=0 to achieve greater than 4
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\n" ); document.write( "\"sqrt%282%2A0%29+=+0\"
\n" ); document.write( "0 + 2 = 2 which is not > 4
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\n" ); document.write( "The first answer takes care of the second.
\n" ); document.write( "x cannot be greater than 2 yet equal to or greater than zero.
\n" ); document.write( "...
\n" ); document.write( "The first answer exludes 1, while the second answer includes it.
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\n" ); document.write( "You first answer was enough to solve the inequality
\n" ); document.write( "x > 2
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\n" ); document.write( "So long as x is > 2, it will always be > 0
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\n" ); document.write( "Delighted to help.
\n" ); document.write( "-Reading Boosters
\n" ); document.write( "Wanting for others what we want for ourselves.
\n" ); document.write( "www.MyHomeworkAnswers.com
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