document.write( "Question 670954: Kristina needs to mix a 30% methanol solution with a 60% methanol solution to create 200 millileters of a 49.5% solution. How many millileters of each solution must Kristina use?\r
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document.write( " Answer: Kristina must mix
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document.write( "millileters of 30% solution and ________________
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document.write( "millileters of 60% solution.____________________ \n" );
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Algebra.Com's Answer #417230 by mananth(16946)![]() ![]() You can put this solution on YOUR website! percent ---------------- quantity \n" ); document.write( "Methanol Solution I 30 ---------------- x ml \n" ); document.write( "Methanol Solution II 60 ------ 200 - x ml \n" ); document.write( "Mixture 50 ---------------- 200 \n" ); document.write( " \n" ); document.write( "30 x + 60 ( 200 - x ) = 49.5 * 200 \n" ); document.write( "3000 x + 6000 ( 200 - x ) = 990000 \n" ); document.write( "3000 x + 1200000 - 6000 x = 990000 \n" ); document.write( "3000 x - 6000 x = 990000 - -1200000 \n" ); document.write( "-3000 x = -210000 \n" ); document.write( "/ -3000 \n" ); document.write( " x = 70 ml 30.00% Methanol Solution I 70ml \n" ); document.write( " 60.00% Methanol Solution II 130 ml \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |