document.write( "Question 670954: Kristina needs to mix a 30% methanol solution with a 60% methanol solution to create 200 millileters of a 49.5% solution. How many millileters of each solution must Kristina use?\r
\n" ); document.write( "\n" ); document.write( " Answer: Kristina must mix
\n" ); document.write( "millileters of 30% solution and ________________
\n" ); document.write( "millileters of 60% solution.____________________
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Algebra.Com's Answer #417230 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "Methanol Solution I 30 ---------------- x ml
\n" ); document.write( "Methanol Solution II 60 ------ 200 - x ml
\n" ); document.write( "Mixture 50 ---------------- 200
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\n" ); document.write( "30 x + 60 ( 200 - x ) = 49.5 * 200
\n" ); document.write( "3000 x + 6000 ( 200 - x ) = 990000
\n" ); document.write( "3000 x + 1200000 - 6000 x = 990000
\n" ); document.write( "3000 x - 6000 x = 990000 - -1200000
\n" ); document.write( "-3000 x = -210000
\n" ); document.write( "/ -3000
\n" ); document.write( " x = 70 ml 30.00% Methanol Solution I 70ml
\n" ); document.write( " 60.00% Methanol Solution II 130 ml
\n" ); document.write( "m.ananth@hotmail.ca
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