document.write( "Question 670910: a chemist needed a 75% acid solution but only has 35% acid and 85% acid solutions. if he uses 120 ml of the 85% solution, how much of the 35% solution is needed to make the 75% solution \n" ); document.write( "
Algebra.Com's Answer #417201 by stanbon(75887)\"\" \"About 
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a chemist needed a 75% acid solution but only has 35% acid and 85% acid solutions. if he uses 120 ml of the 85% solution, how much of the 35% solution is needed to make the 75% solution
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\n" ); document.write( "Equations:
\n" ); document.write( "Quantity: x + y = 120 ml
\n" ); document.write( "Acid::: 35x+85y = 75*120
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\n" ); document.write( "35x + 35y = 35*120
\n" ); document.write( "35x + 85y = 75*120
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\n" ); document.write( "50y = 40(120)
\n" ); document.write( "y = (4/5)120
\n" ); document.write( "y = 96 ml (amt. of 85% solution needed)
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\n" ); document.write( "Solve for \"x\":
\n" ); document.write( "x + y = 120 ml
\n" ); document.write( "x + 96 = 120 ml
\n" ); document.write( "x = 24 ml (amt. of 35% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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