document.write( "Question 670855: If an old guy does a job in 60 hours and an old guy and a new guy does a job in 15 hours, how long does the new guy do it himself? \n" ); document.write( "
Algebra.Com's Answer #417152 by stanbon(75887)\"\" \"About 
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If an old guy does a job in 60 hours and an old guy and a new guy does a job in 15 hours, how long does the new guy do it himself?
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\n" ); document.write( "old guy rate= 1/60 job/hr
\n" ); document.write( "new guy rate= 1/x job/hr
\n" ); document.write( "Together rate= 1/15 job/hr
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\n" ); document.write( "Equation:
\n" ); document.write( "rate + rate = together rate
\n" ); document.write( "1/60 + 1/x = 1/15
\n" ); document.write( "x + 60 = 4x
\n" ); document.write( "3x = 60
\n" ); document.write( "x = 20 hrs (time for the new guy to do the job alone)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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