document.write( "Question 670855: If an old guy does a job in 60 hours and an old guy and a new guy does a job in 15 hours, how long does the new guy do it himself? \n" ); document.write( "
Algebra.Com's Answer #417152 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! If an old guy does a job in 60 hours and an old guy and a new guy does a job in 15 hours, how long does the new guy do it himself? \n" ); document.write( "------- \n" ); document.write( "old guy rate= 1/60 job/hr \n" ); document.write( "new guy rate= 1/x job/hr \n" ); document.write( "Together rate= 1/15 job/hr \n" ); document.write( "------------ \n" ); document.write( "Equation: \n" ); document.write( "rate + rate = together rate \n" ); document.write( "1/60 + 1/x = 1/15 \n" ); document.write( "x + 60 = 4x \n" ); document.write( "3x = 60 \n" ); document.write( "x = 20 hrs (time for the new guy to do the job alone) \n" ); document.write( "============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============= \n" ); document.write( " |