document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=670726>Question 670726</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars, each traveling at a constant rate, leave Boston headed for Philadelphia, 300 miles away. One car travels 10 miles per hour faster and arrives 1 hour earlier than the other car. Determine the rate of the faster car </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #417104 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=417104\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "300=XT<BR>\n" );
document.write( "T=300/X<BR>\n" );
document.write( "AND:<BR>\n" );
document.write( "300=(X+10)(T-1)<BR>\n" );
document.write( "300=(X+10)[(300/X)-1]<BR>\n" );
document.write( "300=300-X+3000/X-10<BR>\n" );
document.write( "0=-X+3000/X-10 MULTIPLY BY -X.<BR>\n" );
document.write( "X^2-3000+10X=0<BR>\n" );
document.write( "X^2+10X-3000=0<BR>\n" );
document.write( "(X-50)(X+60)=0<BR>\n" );
document.write( "X-50=0<BR>\n" );
document.write( "X=50 MPH. ANS. <BR>\n" );
document.write( "300=50T<BR>\n" );
document.write( "T=300/50<BR>\n" );
document.write( "T=6 HOURS ANS.<BR>\n" );
document.write( "300=(50+10)(6-1)<BR>\n" );
document.write( "300=60*5 60 MPH. FOR 5 HOURS FOR THE FASTER CAR.<BR>\n" );
document.write( "300=300 <BR>\n" );
document.write( "   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );