document.write( "Question 670665: A survey of 36 \"iPhone\" owners showed that the purchase price has a sample mean of $450 with a sample standard deviation of $175.\r
\n" ); document.write( "\n" ); document.write( "a) Compute the 95% confidence interval for the mean.
\n" ); document.write( "b) How large a sample is needed to estimate the population mean within $10 at a 99% confidence level?\r
\n" ); document.write( "\n" ); document.write( "Please show all work, calculations, and formulas!!
\n" ); document.write( "

Algebra.Com's Answer #417093 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A survey of 36 \"iPhone\" owners showed that the purchase price has a sample mean of $450 with a sample standard deviation of $175.
\n" ); document.write( "a) Compute the 95% confidence interval for the mean.
\n" ); document.write( "x-bar = 450
\n" ); document.write( "ME = 1.96*175/sqrt(6) = 9.5278
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\n" ); document.write( "95%CI: 450-9.5278 < u < 450+9.5278
\n" ); document.write( "-------------------------------------------
\n" ); document.write( "b) How large a sample is needed to estimate the population mean within $10 at a 99% confidence level?
\n" ); document.write( "n = [z*s/E]^2
\n" ); document.write( "------
\n" ); document.write( "n = [2.5758*175/10]^2 = 2032 when rounded up
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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