document.write( "Question 670665: A survey of 36 \"iPhone\" owners showed that the purchase price has a sample mean of $450 with a sample standard deviation of $175.\r
\n" );
document.write( "\n" );
document.write( "a) Compute the 95% confidence interval for the mean.
\n" );
document.write( "b) How large a sample is needed to estimate the population mean within $10 at a 99% confidence level?\r
\n" );
document.write( "\n" );
document.write( "Please show all work, calculations, and formulas!! \n" );
document.write( "
Algebra.Com's Answer #417093 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A survey of 36 \"iPhone\" owners showed that the purchase price has a sample mean of $450 with a sample standard deviation of $175. \n" ); document.write( "a) Compute the 95% confidence interval for the mean. \n" ); document.write( "x-bar = 450 \n" ); document.write( "ME = 1.96*175/sqrt(6) = 9.5278 \n" ); document.write( "---- \n" ); document.write( "95%CI: 450-9.5278 < u < 450+9.5278 \n" ); document.write( "------------------------------------------- \n" ); document.write( "b) How large a sample is needed to estimate the population mean within $10 at a 99% confidence level? \n" ); document.write( "n = [z*s/E]^2 \n" ); document.write( "------ \n" ); document.write( "n = [2.5758*175/10]^2 = 2032 when rounded up \n" ); document.write( "------------------------------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |