document.write( "Question 670743: Graph this equation f(x)=—(x+2)^2—3 \n" ); document.write( "
Algebra.Com's Answer #417085 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! y = —(x+2)^2—3 \n" ); document.write( "---- \n" ); document.write( "Plot the vertex at (-2,-3) \n" ); document.write( "From there the parabola opens downward because of the negative sign in \n" ); document.write( "from on (x+2)^2. \n" ); document.write( "---- \n" ); document.write( "y-intercept: \n" ); document.write( "Let x = 0, then y = -4-3 = -7 \n" ); document.write( "Plot (0,-7) \n" ); document.write( "--------- \n" ); document.write( "That should be enough to draw the graph of the parabola. \n" ); document.write( "--------- \n" ); document.write( " \n" ); document.write( "==================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |