document.write( "Question 670666: Dr. Susan Breuner is an industrial psychologist. She is studying stress among executives amount internet companies. She has developed a questionnaire that she believes measures stress. A score of 80 indicates stress at a dangerous level. A random sample of 15 executives revealed the following stress level scores:\r
\n" ); document.write( "\n" ); document.write( "90 78 83 90 78 99 97 90 97 90 93 94 100 75 84\r
\n" ); document.write( "\n" ); document.write( "a) Find the sample mean and sample standard deviation.
\n" ); document.write( "b) Construct a 95% confidence interval for the population mean.
\n" ); document.write( "c) Can you conclude that internet executives have a mean stress level in the dangerous level and why?\r
\n" ); document.write( "\n" ); document.write( "Please show all work, calculations, and formulas! Thank you!
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Algebra.Com's Answer #417046 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "A score of 80 indicates stress at a dangerous level
\n" ); document.write( "90 78 83 90 78 99 97 90 97 90 93 94 100 75 84 , \"m+=+89.2\" , \"s+=+7.98\"
\n" ); document.write( "95% confidence level. Degree of freedom = 14, \"+z+=+2.14\"
\n" ); document.write( "ME =\"+2.14%287.98%2Fsqrt%2815%29%29\"
\n" ); document.write( " 89.2 - ME < \"mu\" < 89.2 + ME
\n" ); document.write( "\"z+=+%2889.2-80%29%2F%287.98%2Fsqrt%2815%29%29\" = 4.46, z = 4.46, Yes, dangerous \n" ); document.write( "
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