document.write( "Question 670555: A bag contains x pink balls and y yellow balls. Three balls are radomly selected from the bag. \r
\n" ); document.write( "\n" ); document.write( "a) Write and expression of the probability that three balls chossen were pink. \r
\n" ); document.write( "\n" ); document.write( "Is this right? Because i wansn't sure 3x/x+y ???\r
\n" ); document.write( "\n" ); document.write( "If there had been one more pink ball, then the probabilty that the three balls chosen were pink would have been double the answer found in a \r
\n" ); document.write( "\n" ); document.write( "b) show that y= x^2- x-2 / 5-x\r
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\n" ); document.write( "\n" ); document.write( "Thanks for you help
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Algebra.Com's Answer #417001 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A bag contains x pink balls and y yellow balls. Three balls are radomly selected from the bag.
\n" ); document.write( "a) Write and expression of the probability that three balls chosen were pink.
\n" ); document.write( "Ans: [xC3]/[(x+y)C3]
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\n" ); document.write( "If there had been one more pink ball, then the probabilty that the three balls chosen were pink would have been double the answer found in a
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\n" ); document.write( "(x+1)C3/(x+y+1)C3 = 2[xC3]/(x+y)C3
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\n" ); document.write( "(x+1)C3/xC3 = 2(x+y+1)C3/(x+y)C3
\n" ); document.write( "(x+1)[xC3/xC3] = 2(x+y+1)[(x+y)C3/(x+y)C3]
\n" ); document.write( "(x+1) = 2(x+y+1)
\n" ); document.write( "x+1 = 2x+2y+2
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\n" ); document.write( "b) show that y= x^2- x-2 / 5-x
\n" ); document.write( "Note: That is not what I get as an answer.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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