document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=7540>Question 7540</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The period of a simple pendulum is directly proportional to the<BR>\n" );
document.write( "square root of its length. If a pendulum has a length of 6 feet and a<BR>\n" );
document.write( "period of 2 seconds, to what length should it be shortened to achieve<BR>\n" );
document.write( "a 1 second period? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #4170 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=4170\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Write the proportion:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p+=+k%2Asqrt%28l%29 ALIGN=MIDDLE  ALT=\"p+=+k%2Asqrt%28l%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Substitute the given values of p (2 secs) and l (6 ft.) and solve for k.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2+=+k%2Asqrt%286%29 ALIGN=MIDDLE  ALT=\"2+=+k%2Asqrt%286%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=k+=+2%2Fsqrt%286%29 ALIGN=MIDDLE  ALT=\"k+=+2%2Fsqrt%286%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Now you can write:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28l%29+=+p%2Fk ALIGN=MIDDLE  ALT=\"sqrt%28l%29+=+p%2Fk\"   DISABLED_style= \"max-width:90%; height:auto;\" > Square both sides to find l.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=l+=+%28p%2Fk%29%5E2 ALIGN=MIDDLE  ALT=\"l+=+%28p%2Fk%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Now substitute the values for <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p+=%281+sec%29 ALIGN=MIDDLE  ALT=\"p+=%281+sec%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=k+=2%2Fsqrt%286%29 ALIGN=MIDDLE  ALT=\"k+=2%2Fsqrt%286%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > then solve for l.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=l+=+%281%2F%282%2Fsqrt%286%29%29%29%5E2 ALIGN=MIDDLE  ALT=\"l+=+%281%2F%282%2Fsqrt%286%29%29%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=l+=+%28sqrt%286%29%2F2%29%5E2 ALIGN=MIDDLE  ALT=\"l+=+%28sqrt%286%29%2F2%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=l+=+6%2F4 ALIGN=MIDDLE  ALT=\"l+=+6%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "l = 1.5 ft. </SPAN>\n" );
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