document.write( "Question 670451: log[4]80 \n" ); document.write( "

Algebra.Com's Answer #416981 by lwsshak3(11628) $\"\"$ $\"About$

You can put this solution on YOUR website!
log[4]80=x
\n" ); document.write( "convert to exponential form
\n" ); document.write( "4^x=80
\n" ); document.write( "takelog of both sides
\n" ); document.write( "xlog4=log80
\n" ); document.write( "x=log80/log4≈3.161
\n" ); document.write( "log[4]80≈3.161 \n" ); document.write( "

\n" );