document.write( "Question 670541: the product of two integers is 80. one number is 8 more than 3 times the other number. find the number. \n" ); document.write( "

Algebra.Com's Answer #416970 by mananth(16946) $\"\"$ $\"About$

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let the integers be x & y\r
\n" ); document.write( "\n" ); document.write( "xy=80
\n" ); document.write( "OR
\n" ); document.write( "x=80/y\r
\n" ); document.write( "\n" ); document.write( "x=3y+8\r
\n" ); document.write( "\n" ); document.write( "3y+8= 80/y\r
\n" ); document.write( "\n" ); document.write( "multiply equation by y
\n" ); document.write( "3y^2+8y=80
\n" ); document.write( "3y^2+8y-80=0
\n" ); document.write( "a= 3 b= 8 c= -80
\n" ); document.write( "
\n" ); document.write( "b^2-4ac= 64 - -960
\n" ); document.write( "b^2-4ac= 1024
\n" ); document.write( " $\"sqrt%28%091024%09%29\"$ = 32
\n" ); document.write( " $\"y=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"$
\n" ); document.write( " $\"y1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"$ )/
\n" ); document.write( "y1=( -8 + 32 )/ 6
\n" ); document.write( "y1= 4
\n" ); document.write( "y2=( -8 - 32 )/ 6
\n" ); document.write( "y2= -6.67
\n" ); document.write( "Ignore negative value it is not an integer
\n" ); document.write( "y = 4 \r
\n" ); document.write( "\n" ); document.write( "The integers are 4 & 20
\n" ); document.write( " \n" ); document.write( "

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