document.write( "Question 670533: Two pumps can drain a pool in 36 hours. The older pump alone takes 30 hours longer to drain the pool than the newer one does alone. How long does the newer pump take to drain the pool? \n" ); document.write( "
Algebra.Com's Answer #416968 by mananth(16946)\"\" \"About 
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New pump x hours
\n" ); document.write( "Old pump x+ 30 hours
\n" ); document.write( "New pump 1/x of the job in hour
\n" ); document.write( "Old pump 1/(x+ 30 )of the job in 1 hour
\n" ); document.write( "Together they take 1/x+ 1/(x+30 )of the job in 1 hour
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\n" ); document.write( "Together they do 1/36 of the job in 1 hour
\n" ); document.write( "1/x + 1/(x+30 )= 1/ 36
\n" ); document.write( "LCD =x(x+30)
\n" ); document.write( "(x+30)+x=1/36(x+30)x
\n" ); document.write( "( 2x+30 ) *36 = x^2+ 30 x
\n" ); document.write( "72 x+ 1080 = x^2+ 30 x
\n" ); document.write( "x^2 -42 x -1080 = 0
\n" ); document.write( "Find the roots of the equation by quadratic formula
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\n" ); document.write( "a= 1 b= -42 c= -1080
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\n" ); document.write( "b^2-4ac= 1764 - -4320
\n" ); document.write( "b^2-4ac= 6084 \"sqrt%28%096084%09%29\"= 78
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\" )/
\n" ); document.write( "x1=( 42 + 78 )/ 2
\n" ); document.write( "x1= 60
\n" ); document.write( "x2=( 42 - 78 )/ 2
\n" ); document.write( "x2= -18
\n" ); document.write( "Ignore negative value
\n" ); document.write( "x = 60 hours Time taken by new pump
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