document.write( "Question 670538: With the current you can row 24 miles in 3 hours. Against the same current, you can row only 2/3 of this distance in 4 hours. Find your rowing rate in still water and the rate of the current \n" ); document.write( "
Algebra.Com's Answer #416967 by mananth(16946)\"\" \"About 
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Rowing speed =x mph
\n" ); document.write( "current speed =y mph
\n" ); document.write( "against current 4 hours
\n" ); document.write( "with current 3 hours
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\n" ); document.write( "Distance against 16 miles distance with wind 24 miles
\n" ); document.write( "t=d/r against wind -
\n" ); document.write( "16 / ( x - y )= 4
\n" ); document.write( "4 ( x - y ) = 16
\n" ); document.write( "4 x - 4 y = 16 ....................1
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\n" ); document.write( "24 / ( x y y )= 3
\n" ); document.write( "3 ( x + y ) = 24
\n" ); document.write( "3 x + 3 y = 24 ...............2
\n" ); document.write( "Multiply (1) by 1
\n" ); document.write( "Multiply (2) by 1
\n" ); document.write( "we get y
\n" ); document.write( "4 x + -4 y = 16
\n" ); document.write( "3 x + 3 = 24
\n" ); document.write( "7 x = 40
\n" ); document.write( "/ 7
\n" ); document.write( "x = 6 mph
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\n" ); document.write( "plug value of x in (1) y
\n" ); document.write( "4 x -4 y = 16
\n" ); document.write( "23 -4 -23 = 16
\n" ); document.write( "-4 y = 16
\n" ); document.write( "-4 y = -7 mph
\n" ); document.write( " y = 2
\n" ); document.write( "Rowing speed 6 mph
\n" ); document.write( "current speed 2 mph
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\n" ); document.write( "m.ananth@hotmail.ca
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