document.write( "Question 670506: The width of a widescreen TV is 10 in. less than its length. The diagonal of the rectangular screen is 10 in. more than the length. Find the length and width of the screen.\r
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document.write( "How do I set this up and solve? \n" );
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Algebra.Com's Answer #416956 by mananth(16946)![]() ![]() You can put this solution on YOUR website! length =x\r \n" ); document.write( "\n" ); document.write( "width = (x-10 )\r \n" ); document.write( "\n" ); document.write( "diagonal = (x+10)\r \n" ); document.write( "\n" ); document.write( "They form a right triangle. \n" ); document.write( "Apply Pythagoras theorem\r \n" ); document.write( "\n" ); document.write( "(x+10)^2=x^2+ (x-10)^2\r \n" ); document.write( "\n" ); document.write( "x^+20x+100=x^2+x^2-20x+100\r \n" ); document.write( "\n" ); document.write( "2x^2=40x \n" ); document.write( "/x \n" ); document.write( "2x=40 \n" ); document.write( "x= 20 the length of the TV\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |