document.write( "Question 670469: Kevin flies(in his private plane) from Los Angeles to San Franciso, a distance of 450 miles, in 3 hours. He flies back in 2 7/19 hours. If the wind is blowing from the north at a steady rate during both flights, find the airspeed of the plane and the velocity of the wind. \n" ); document.write( "

Algebra.Com's Answer #416955 by mananth(16946) $\"\"$ $\"About$

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Plane speed =x mph
\n" ); document.write( "wind speed =y mph
\n" ); document.write( "against wind 3 hours
\n" ); document.write( "with wind 45/19 hours
\n" ); document.write( "
\n" ); document.write( "Distance against 450 miles distance with wind 450 miles
\n" ); document.write( "t=d/r against wind -
\n" ); document.write( "450 / ( x - y )= 3
\n" ); document.write( "3 ( x - y ) = 450
\n" ); document.write( "3 x - 3 y = 450
\n" ); document.write( "x-y=150....................1
\n" ); document.write( "
\n" ); document.write( "450 / ( x + y )= 45/19
\n" ); document.write( "45/19 ( x + y ) = 450
\n" ); document.write( "45/19 x + 45/19 y = 450
\n" ); document.write( "x+y=190...............2 \r
\n" ); document.write( "\n" ); document.write( "add the two equations (1) & (2)
\n" ); document.write( "2x=340
\n" ); document.write( "/2
\n" ); document.write( "x=170 speed of plane\r
\n" ); document.write( "\n" ); document.write( "Therefore speed of wind = 20 mph \n" ); document.write( "

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