document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=670499>Question 670499</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 12 liter mixture is 60% alcohol. If 8 liters of a 25% alcohol mixture are added,what percent mixture will be formed?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #416944 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=416944\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let	x be	the percent age of the mixyure								<BR>\n" );
document.write( "	Percent	----------------			quantity					<BR>\n" );
document.write( "Alcohol I	60	----------------			12	liters				<BR>\n" );
document.write( "Alcohol II	25	----------------			8	liters				<BR>\n" );
document.write( "Total	x	----------------			20	liters				<BR>\n" );
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document.write( "15*60+8	*25=20x<BR>\n" );
document.write( "900+200	=20x				<BR>\n" );
document.write( "1100=20x						<BR>\n" );
document.write( "/	20								<BR>\n" );
document.write( "1100	/	20	=	x					<BR>\n" );
document.write( "55	=	x							<BR>\n" );
document.write( "the percent age of the mixyure		is			55					<BR>\n" );
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