document.write( "Question 670326: find two consecutive integers such that 4 times the lesser is 8 more than 3 times the greater \n" ); document.write( "
Algebra.Com's Answer #416904 by VirtualMathTutor(26)\"\" \"About 
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let x be the first number
\n" ); document.write( "let x + 1 be the second number\r
\n" ); document.write( "\n" ); document.write( "4 times the lesser number (which is x) is 8 more than 3 times the greater (which is x + 1)\r
\n" ); document.write( "\n" ); document.write( "4x = 8 + 3(x + 1)\r
\n" ); document.write( "\n" ); document.write( "4x = 8 + 3x + 3\r
\n" ); document.write( "\n" ); document.write( "4x = 11 + 3x\r
\n" ); document.write( "\n" ); document.write( "subtract 3x from both sides\r
\n" ); document.write( "\n" ); document.write( "x = 11\r
\n" ); document.write( "\n" ); document.write( "The second number is x + 1 = 11 + 1 = 12\r
\n" ); document.write( "\n" ); document.write( "So the consecutive numbers are 11 and 12
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