document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=60718>Question 60718</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 6x2 - 13x + 6 = 0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41686 by </B><A HREF=/tutors/aboutme.mpl?userid=funmath><B>funmath(2933)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=funmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41686\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6x^2-13x+6=0<BR>\n" );
document.write( "We need to factor the left side which is in standard form:<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ax%5E2%2Bbx%2Bc ALIGN=MIDDLE  ALT=\"ax%5E2%2Bbx%2Bc\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "a=6, b=-13, and c=6<BR>\n" );
document.write( "Replace the middle term with two numbers that multiply to give you a*c=6*6=26, but add to give you b=-13.  -4*-9=36 and -4+-9=-13<BR>\n" );
document.write( "6x^2-4x-9x+6=0  Factor by grouping<BR>\n" );
document.write( "(6x^2-4x)+(-9x+6)=0  group<BR>\n" );
document.write( "2x(3x-2)-3(3x-2)=0  factor out the GCF in each group<BR>\n" );
document.write( "(3x-2)(2x-3)=0  Factor the 3x-2 out of each.<BR>\n" );
document.write( "3x-2=0  and 2x-3=0<BR>\n" );
document.write( "3x=2 and 2x=3<BR>\n" );
document.write( "3x/3=2/3 and 2x/2=3/2<BR>\n" );
document.write( "x=2/3 and x=3/2<BR>\n" );
document.write( "Happy Calculating!!!<BR>\n" );
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