document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=670253>Question 670253</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For question #276198. Can someone explain the reasoning as to how this problem was solved. For example, I know that Moulders's distance = Scully's distance, that r*t  = r*t. But why does 1/2 hr get added to Moulder's time? Does this mean he spends more time traveling his distance? (when you go back and plug in the answer 10 5/6 hrs into the equation, it's basically a distance equals distance equation, and this shows that Moulder takes longer to travel his distance. This is what I am basing my questions on.)\r<BR>\n" );
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document.write( "Also, how does this fit in with when Scully catches up with Moulder?\r<BR>\n" );
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document.write( "Thanks Ralph </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #416854 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10555)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=416854\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "For question #276198. Can someone explain the reasoning as to how this problem was solved. For example, I know that Moulders's distance = Scully's distance, that r*t  = r*t. But why does 1/2 hr get added to Moulder's time? Does this mean he spends more time traveling his distance? (when you go back and plug in the answer 10 5/6 hrs into the equation, it's basically a distance equals distance equation, and this shows that Moulder takes longer to travel his distance. This is what I am basing my questions on.)\r<BR>\n" );
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document.write( "Also, how does this fit in with when Scully catches up with Moulder?\r<BR>\n" );
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document.write( "Thanks Ralph\r<BR>\n" );
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document.write( "Let the time taken by Molder to get to the “catch-up” point be T<BR>\n" );
document.write( "Then time taken by Scholy to get to the “catch-up” point is T – ½hour<BR>\n" );
document.write( "Molder is going to take a longer time to get to the “catch-up” point since he’s traveling at a slower speed\r<BR>\n" );
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document.write( "When Scoly catches up to Molder, both would’ve traveled the same distance<BR>\n" );
document.write( "We therefore form a distance equation…one that says: <BR>\n" );
document.write( "Molder’s distance traveled to “catch-up” point = Scholy’s distance traveled to the “catch-up” point, which is algebraically written as:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=65T+=+68%28T+-+1%2F2%29 ALIGN=MIDDLE  ALT=\"65T+=+68%28T+-+1%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "65T = 68T – 34<BR>\n" );
document.write( "65T – 68T = - 34 <BR>\n" );
document.write( "– 3T = - 34<BR>\n" );
document.write( "T, or time it’ll take Molder to get to “catch-up” point = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-+34%29%2F-+3 ALIGN=MIDDLE  ALT=\"%28-+34%29%2F-+3\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=11%261%2F3 ALIGN=MIDDLE  ALT=\"11%261%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > hours, or 11 hours, 20 minutes\r<BR>\n" );
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document.write( "After leaving at 8:30 AM, and after traveling for 11 hours, 20 minutes to get to “catch-up” point, Molder will reach “catch-up” point at <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%287%3A50%29 ALIGN=MIDDLE  ALT=\"highlight_green%287%3A50%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > PM. \r<BR>\n" );
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document.write( "Yes, Molder does take a longer time to cover the same distance as Scholy  since he (Molder) is traveling at a slower rate of speed (65 mph as opposed to Scholy's 68 mph). \r<BR>\n" );
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document.write( "Additionally, you can either let Molder's time be T, and subtract 1/2 hour to get Scholy's time, or let Scholy's time be T, and then add 1/2 hour to get Molder's time. \r<BR>\n" );
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document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com </SPAN>\n" );
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