document.write( "Question 669998: One hour after a truck has left on an overnight haul, a messenger on a motorcycle leaves from the same starting point to overtake the truck. If the messenger travels at an average rate of 65 mi/hr and overtakes the truck in 4 hr, what is the average rate of the truck? \n" ); document.write( "
Algebra.Com's Answer #416850 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
One hour after a truck has left on an overnight haul, a messenger on a motorcycle
\n" ); document.write( " leaves from the same starting point to overtake the truck.
\n" ); document.write( " If the messenger travels at an average rate of 65 mi/hr and overtakes the truck
\n" ); document.write( " in 4 hr, what is the average rate of the truck?
\n" ); document.write( ":
\n" ); document.write( "Let t = av rate of the truck (truck's travel time = 5 hrs)
\n" ); document.write( ":
\n" ); document.write( "When the bike overtakes the truck, they will have traveled the same distance
\n" ); document.write( "Write a distance equation; dist = rate * time
\n" ); document.write( ":
\n" ); document.write( "Truck dist = bike dist
\n" ); document.write( "5t = 4*65
\n" ); document.write( "5t = 260
\n" ); document.write( "t = \"260%2F5\"
\n" ); document.write( "t = 52 mph is the truck speed
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this by finding the actual distance each traveled
\n" ); document.write( "Truck: 5(52) = 260 mi
\n" ); document.write( "Bike: 4(65) = 260 mi \n" ); document.write( "
\n" );