document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=670239>Question 670239</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, I'm having trouble on this problem. at 10:00am,a car leaves a house at a rate of 60 mph. At the same time, another car leaves the same house at a rate of 50 mph in the opposite direction. At what time will the cars by 330 miles apart? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #416833 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=416833\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since they are travelling in opposite directions, it is like one car going at the sum of the two speeds or<BR>\n" );
document.write( "(1) d = (r1 + r2)*t or using the values you are given<BR>\n" );
document.write( "(2) 330 = (60 + 50)*t or<BR>\n" );
document.write( "(3) 330 = 110*t which gives<BR>\n" );
document.write( "(4) t = 330/110 or<BR>\n" );
document.write( "(5) t = 3<BR>\n" );
document.write( "Lets check this value of time by calculating the distance each car travels in 3 hours.<BR>\n" );
document.write( "(6) d1 = 60*3 or<BR>\n" );
document.write( "(7) d1 = 180 mi<BR>\n" );
document.write( "and<BR>\n" );
document.write( "(8) d2 = 50*3 or<BR>\n" );
document.write( "(9) d2 = 150 mi<BR>\n" );
document.write( "Is (d1 + d2 = 330)?<BR>\n" );
document.write( "Is (180 + 150 =330)?<BR>\n" );
document.write( "Is (330 = 330)? Yes<BR>\n" );
document.write( "Answer: The cars will 330 miles apart at 1:00 pm the same day. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );