document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=670085>Question 670085</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much of an alloy that is 30 percent should be mixed with 600 ounces of an alloy that is 70 percent copper in order to get an alloy that is 50 percent copper </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #416766 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=416766\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how much of an alloy that is 30 percent should be mixed with 600 ounces of an alloy that is 70 percent copper in order to get an alloy that is 50 percent copper<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "active + active = active<BR>\n" );
document.write( "0.30x + 0.70*600 = 0.50(x+600)<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "30x + 70*600 = 50x + 50*600<BR>\n" );
document.write( "20x = 20*600<BR>\n" );
document.write( "x = 600 ounces (amt. of 30% alloy needed)<BR>\n" );
document.write( "======================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );