document.write( "Question 669925: Carol has 8 hours to spend on a hike up a mountain and back again. She can walk up the trail at an average of 2 mph and can walk down at an average of 3 mph. How long should she plan to spend on the uphill part of the hike? \n" ); document.write( "
Algebra.Com's Answer #416714 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Carol has 8 hours to spend on a hike up a mountain and back again.
\n" ); document.write( " She can walk up the trail at an average of 2 mph and can walk down at an average of 3 mph.
\n" ); document.write( " How long should she plan to spend on the uphill part of the hike?
\n" ); document.write( ":
\n" ); document.write( "let t = time spent walking up-hill
\n" ); document.write( "then
\n" ); document.write( "(8-t) = time walking down
\n" ); document.write( ";
\n" ); document.write( "Write a distance equation; dist = speed * time. (distance up and down are equal)
\n" ); document.write( "2t = 3(8-t)
\n" ); document.write( "2t = 24 - 3t
\n" ); document.write( "2t + 3t = 24
\n" ); document.write( "5t = 24
\n" ); document.write( "t = 24/5
\n" ); document.write( "t = 4.8 hrs walking up
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this by finding the distances
\n" ); document.write( "2(4.8) = 9.6 mi
\n" ); document.write( "3(8-4.8) = 9.6 mi \n" ); document.write( "
\n" );