document.write( "Question 669964: A lady drove to a city 30 miles away to shop and returned home in the evening. She spent15 minutes longer driving the return trip than in the going, and she drover three-fourths as fast when returning as she did when going to the city. How long did it take her to drive to the city? \n" ); document.write( "
Algebra.Com's Answer #416712 by ankor@dixie-net.com(22740)\"\" \"About 
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A lady drove to a city 30 miles away to shop and returned home in the evening.
\n" ); document.write( " She spent15 minutes longer driving the return trip than in the going, and she
\n" ); document.write( " drover three-fourths as fast when returning as she did when going to the city.
\n" ); document.write( " How long did it take her to drive to the city?
\n" ); document.write( ":
\n" ); document.write( "Find the speed first
\n" ); document.write( "let s = speed to the city
\n" ); document.write( "then
\n" ); document.write( ".75s = return speed
\n" ); document.write( ":
\n" ); document.write( "Change 15 min to .25 hr
\n" ); document.write( ":
\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( "\"30%2Fs\" + .25 = \"30%2F%28.75s%29\"
\n" ); document.write( "multiply by 3s, to clear the denominators, results
\n" ); document.write( "3(30) + 3s(.25) = 4(30)
\n" ); document.write( "90 + .75s = 120
\n" ); document.write( ".75s = 120 - 90
\n" ); document.write( ".75s = 30
\n" ); document.write( "s = 30/.75
\n" ); document.write( "s = 40 mph to the city
\n" ); document.write( ":
\n" ); document.write( "Find the time
\n" ); document.write( "30/40 = .75 hrs or 45 min to drive to the city\r
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