document.write( "Question 60669This question is from textbook Essential Algebra
\n" ); document.write( ": Hi, I am new to geometry. I am a distance education student and cannot fiqure out where to start. \r
\n" ); document.write( "\n" ); document.write( "The problem is: Find the volume and surface area of a rectangular solid, if its
\n" ); document.write( "length is 10 inches, its width is 5 inches, and it is twice as wide as it is deep.\r
\n" ); document.write( "\n" ); document.write( "Thanks for your help,
\n" ); document.write( "Lee Ann
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Algebra.Com's Answer #41670 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Well, a rectangular solid has six faces, opposite pairs of which are identical.\r
\n" ); document.write( "\n" ); document.write( "To find the volume of a rectangular solid, use the formula:
\n" ); document.write( "\"V+=+l%2Aw%2Ah\" Where: l = the length, w = the width, and h = the height.\r
\n" ); document.write( "\n" ); document.write( "You are given the length: l = 10\" and the width, w = 5\"
\n" ); document.write( "If it is twice as wide as it is deep (same as height).
\n" ); document.write( "So, 2h = w and h = (1/2)w = (1/2)5 = 2.5\r
\n" ); document.write( "\n" ); document.write( "The volume is:
\n" ); document.write( "\"V+=+%2810%29%285%29%282.5%29\"
\n" ); document.write( "\"V+=+125\"cu. ins.\r
\n" ); document.write( "\n" ); document.write( "To find the surface area of the six faces, find the areas of the three pairs of identical faces (2 sides, 2 ends, top & bottom).\r
\n" ); document.write( "\n" ); document.write( "One side: \"A1+=+l%2Ah\" = \"%2810%29%2A%282.5%29+=+25\" Multiply by 2 for both sides.
\n" ); document.write( "\"2A1+=+2%2825%29\" = \"50\" sq. ins.\r
\n" ); document.write( "\n" ); document.write( "For one end: \"A2+=+w%2Ah\" = \"%285%29%2A%282.5%29+=+12.5\" Multiply by 2 for both ends.
\n" ); document.write( "\"2A2+=+2%2812.5%29\" = \"25\" sq. ins.\r
\n" ); document.write( "\n" ); document.write( "For the top: \"A3+=+l%2Aw\" = \"%2810%29%285%29+=+50\" Multiply by 2 for both top & bottom.
\n" ); document.write( "\"2A3+=+2%2850%29\" + \"100\" sq. ins.\r
\n" ); document.write( "\n" ); document.write( "Total surface area is: \"2A1+%2B+2A2+%2B+2A3+=+50+%2B+25+%2B+100\" = \"175\" sq. ins.
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