document.write( "Question 669962: David is 3 years older than his brother John. Three years ago John's age was 6 more than one-fourth of David's age. What are their present ages? I have been confused and frustrated for hours please help! \n" ); document.write( "
Algebra.Com's Answer #416655 by ReadingBoosters(3246)\"\" \"About 
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D = J+3
\n" ); document.write( "J-3 = 6 + \"1%2F4\"D
\n" ); document.write( "...
\n" ); document.write( "J-3 = 6 + \"1%2F4\"(J+3)
\n" ); document.write( "J-3 = 6 + \"1%2F4J+%2B+3%2F4\"
\n" ); document.write( "...
\n" ); document.write( "J - \"1%2F4\"J = 6 + \"3%2F4\" + 3
\n" ); document.write( "\"3%2F4\"J = 9 + \"3%2F4\"
\n" ); document.write( "\"3%2F4\"J = \"39%2F4\"
\n" ); document.write( "J = \"%2839%2F4%29%284%2F3%29\"
\n" ); document.write( "\"highlight_green%28J+=+13%29\" years old
\n" ); document.write( "...
\n" ); document.write( "D = 13 + 3
\n" ); document.write( "\"highlight_green%28D+=+16%29\" years old
\n" ); document.write( "...
\n" ); document.write( "Check
\n" ); document.write( "13 - 3 = 10
\n" ); document.write( "6 + \"1%2F4\"(16) = 10
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