document.write( "Question 669843: An object is thrown from the origin of a coordinate system with the x-axis along the ground and the y-axis vertical. Its path, or trajectory, is given by the equation y = 400x – 16x2. \r
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\n" ); document.write( "\n" ); document.write( "b. Find the objects maximum height.\r
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Algebra.Com's Answer #416607 by mananth(16946)\"\" \"About 
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y=400x-16x^2\r
\n" ); document.write( "\n" ); document.write( " Where: y = height and x = time.
\n" ); document.write( "The maximum height occurs at the vertex of the parabola whose x-coordinate is \"-b%2F2a\" in the quadratic equation ax^2+bx+c.
\n" ); document.write( " a = -16, b = 400, and c = 0. \r
\n" ); document.write( "\n" ); document.write( "\"-b%2F2a%29=+-400%2F-32\"\r
\n" ); document.write( "\n" ); document.write( "=12.6 seconds The time at maximum height. \r
\n" ); document.write( "\n" ); document.write( "Substitute this value of x into the original equation and solve for y to get the maximum height. \r
\n" ); document.write( "\n" ); document.write( "\"y=400x-16x%5E2\"
\n" ); document.write( "\"y=400%2A12.5-16%2812.5%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "=2500 feet maximum height reached by the object.\r
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