document.write( "Question 669843: An object is thrown from the origin of a coordinate system with the x-axis along the ground and the y-axis vertical. Its path, or trajectory, is given by the equation y = 400x – 16x2. \r
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document.write( "a. For what value of x does the object reach maximum height?\r
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document.write( "b. Find the objects maximum height.\r
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Algebra.Com's Answer #416607 by mananth(16946)![]() ![]() You can put this solution on YOUR website! y=400x-16x^2\r \n" ); document.write( "\n" ); document.write( " Where: y = height and x = time. \n" ); document.write( "The maximum height occurs at the vertex of the parabola whose x-coordinate is \n" ); document.write( " a = -16, b = 400, and c = 0. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "=12.6 seconds The time at maximum height. \r \n" ); document.write( "\n" ); document.write( "Substitute this value of x into the original equation and solve for y to get the maximum height. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "=2500 feet maximum height reached by the object.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |