document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=669862>Question 669862</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 50% acid solution must be mixed with 40  gallons of a 19% solution to obtain a solution that is 40% acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #416601 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=416601\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -------------- 	percent	----------------	Amount									<BR>\n" );
document.write( "Acid solution I	19	----------------			40	gallons						<BR>\n" );
document.write( "Acid solution II	50	----------------			x	gallons						<BR>\n" );
document.write( "Mixture	40	----------------	40	+	x	gallons						<BR>\n" );
document.write( "												<BR>\n" );
document.write( "19*40+50x=40(40	+x)<BR>\n" );
document.write( "760+50	x	=	1600	+	40	x				<BR>\n" );
document.write( "50x-40	x=-760+	1600				<BR>\n" );
document.write( "10	x	=	840									<BR>\n" );
document.write( "/	10											<BR>\n" );
document.write( "x	=	84		gallons	Acid solution II							<BR>\n" );
document.write( "												<BR>\n" );
document.write( "m.ananth@hotmail.ca												<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );