document.write( "Question 669832: Can someone please help me understand this! \r
\n" ); document.write( "\n" ); document.write( "Suppose we have a population of scores with a mean (μ) of 975 and a standard deviation (σ) of 15. Assume that the distribution is normal. Provide answers to the following questions:
\n" ); document.write( "a. What percentage of the population will lie between 960 and 990?
\n" ); document.write( "b. What percentage of the population will lie below 975?
\n" ); document.write( "c. What percentage of the population will lie below 990?
\n" ); document.write( "d. What two values of X (the counts) would encompass the middle 50 percent of scores?
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Algebra.Com's Answer #416588 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Suppose we have a population of scores with a mean (μ) of 975 and a standard deviation (σ) of 15. Assume that the distribution is normal. Provide answers to the following questions:
\n" ); document.write( "a. What percentage of the population will lie between 960 and 990?
\n" ); document.write( "z(960) = (960-975)/15 = -15/15 = -1
\n" ); document.write( "z(990) = (990-975)/15 = 15/15 = 1
\n" ); document.write( "----
\n" ); document.write( "P(960<= x <= 990) = P(-1<= z <=1) = 0.6827
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\n" ); document.write( "b. What percentage of the population will lie below 975?
\n" ); document.write( "z(975) = (975-975)/15 = 0
\n" ); document.write( "P(x > 975) = P(z < 0) = 0.50
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\n" ); document.write( "c. What percentage of the population will lie below 990?
\n" ); document.write( "P(x < 990) = P(z < 1) = 0.8413
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\n" ); document.write( "d. What two values of X (the counts) would encompass the middle 50 percent of scores?
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\n" ); document.write( "Find the z-value with a left tail of 25%
\n" ); document.write( "invNorm(0.25) = -0.6745
\n" ); document.write( "By symmetry the z-value with a right tail of 25% is 0.6745
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\n" ); document.write( "Find the corresponding x-values using x = z*s + u
\n" ); document.write( "Lower limit: x = -0.6745*15+975 = 964.88
\n" ); document.write( "Upper limit: x = 0.6745*15+975 = 985.12
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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