document.write( "Question 669773: log(x^2+5x+16)=1 \n" ); document.write( "

Algebra.Com's Answer #416586 by Theo(13342) $\"\"$ $\"About$

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log (x^2 + 5x + 16) = 1
\n" ); document.write( "since log(a) = b if and only if 10^b = a, your equations can be changed to be:
\n" ); document.write( "10^1 = x^2 + 5x + 16 which becomes:
\n" ); document.write( "x^2 + 5x + 16 = 10
\n" ); document.write( "subtract 10 from both sides of the equation to get:
\n" ); document.write( "x^2 + 5x + 6 = 0
\n" ); document.write( "the roots of that equation are at:
\n" ); document.write( "x = -2
\n" ); document.write( "x = -3
\n" ); document.write( "to confirm, substitute these values into the original equations to see if the original equation holds true.
\n" ); document.write( "the original equation is:
\n" ); document.write( "log (x^2 + 5x + 16) = 1
\n" ); document.write( "when you substitute -2 for x and when you substitute -3 for x, the equation holds true confirming the solution is good.
\n" ); document.write( "the solution to the equation is:
\n" ); document.write( "x = -2 or x = -3
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