document.write( "Question 60611: If Lane invested $22,000, part at 8% and part at 7%. If the total interest at the end of the year is $1,710, how much did she invest at 8% \n" ); document.write( "
Algebra.Com's Answer #41655 by checkley71(8403)\"\" \"About 
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.08X+.07(22000-X)=1710
\n" ); document.write( ".08X+1540-.07X=1710
\n" ); document.write( ".01X=1710-1540
\n" ); document.write( ".01X=170
\n" ); document.write( "X=170/.01
\n" ); document.write( "X=17000 AMOUNT INVESTED @ 8%
\n" ); document.write( "22000-17000=5000 INVESTED @ 7%
\n" ); document.write( "PROOF
\n" ); document.write( ".08*17000+.07*5000=1710
\n" ); document.write( "1360+350=1710
\n" ); document.write( "1710=1710
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