document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=669665>Question 669665</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The stated problem: Given that the polynomial function has the given zero, find the other zeros. f(x)= x to the third minus 4x squared + 14x -20; the given zero is two. <BR>\n" );
document.write( "I am able to get to the end by using division or synthetic division with a final quotient of: x squared -2x+10 then use that in a quadratic equation and end with 2 + or - 6 divided by two. My answer (which is wrong is 1+3, 1-3)The correct answer is 1+3i & 1-3i & of course -2. I don't understand. Please if you can, explain. Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #416531 by </B><A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><B>ReadingBoosters(3246)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=416531\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> when you were on this step...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2+-+2x+%2B+1+=+-9 ALIGN=MIDDLE  ALT=\"x%5E2+-+2x+%2B+1+=+-9\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-1%29%5E2+=+-9 ALIGN=MIDDLE  ALT=\"%28x-1%29%5E2+=+-9\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x-1+=+%2B-+sqrt%28-9%29 ALIGN=MIDDLE  ALT=\"x-1+=+%2B-+sqrt%28-9%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "...<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1+%2B-+sqrt%28-9%29 ALIGN=MIDDLE  ALT=\"1+%2B-+sqrt%28-9%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "...<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1+%2B-+sqrt%283%2A3%2A-1%29 ALIGN=MIDDLE  ALT=\"1+%2B-+sqrt%283%2A3%2A-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "...<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1+%2B-+3sqrt%28-1%29 ALIGN=MIDDLE  ALT=\"1+%2B-+3sqrt%28-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "where i = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28-1%29 ALIGN=MIDDLE  ALT=\"sqrt%28-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "...<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1+%2B-+3i ALIGN=MIDDLE  ALT=\"1+%2B-+3i\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "...<BR>\n" );
document.write( "giving the answer<BR>\n" );
document.write( "1 + 3i, 1-3i and 2<BR>\n" );
document.write( ".....................<BR>\n" );
document.write( "Delighted to help.<BR>\n" );
document.write( "-Reading Boosters<BR>\n" );
document.write( "Wanting for others what we want for ourselves.<BR>\n" );
document.write( "www.MyHomeworkAnswers.com<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );