document.write( "Question 669455: twice a number exceeds 24 by as much as twice a second number is less than 80.thrice the first number divided by 5 is equal to the second number divided by 4. find the numbers \n" ); document.write( "
Algebra.Com's Answer #416508 by ankor@dixie-net.com(22740)\"\" \"About 
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Two numbers, a & a
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\n" ); document.write( "twice a number exceeds 24 by as much as twice a second number is less than 80.
\n" ); document.write( "2a - 24 = 80 - 2b
\n" ); document.write( "2a + 2b = 80 + 24
\n" ); document.write( "2a + 2b = 104
\n" ); document.write( "Simplify, divide by 2
\n" ); document.write( "a + b = 52
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\n" ); document.write( "thrice the first number divided by 5 is equal to the second number divided by 4.
\n" ); document.write( "\"%283a%29%2F5\" = \"b%2F4\"
\n" ); document.write( "cross multiply
\n" ); document.write( "4(3a) = 5b
\n" ); document.write( "12a = 5b
\n" ); document.write( "12a - 5b = 0
\n" ); document.write( " 5a + 5b = 260 multiplied the 1st equation by 5
\n" ); document.write( "-------------- addition eliminates b, find a
\n" ); document.write( "17a = 260
\n" ); document.write( "a ~ 15.294, I would have expected integers here, anyway
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\n" ); document.write( "a + b = 52
\n" ); document.write( "15.294 + b = 52
\n" ); document.write( "b = 52 - 15.294
\n" ); document.write( "b = 36.706
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\n" ); document.write( "See if that satisfies the 2nd statement, using a calc:
\n" ); document.write( "\"%283%2A15.294%29%2F5\" = \"36.706%2F4\"
\n" ); document.write( "9.1764 ~ 9.1765, close anyway\r
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