document.write( "Question 669455: twice a number exceeds 24 by as much as twice a second number is less than 80.thrice the first number divided by 5 is equal to the second number divided by 4. find the numbers \n" ); document.write( "
Algebra.Com's Answer #416508 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Two numbers, a & a \n" ); document.write( "; \n" ); document.write( "twice a number exceeds 24 by as much as twice a second number is less than 80. \n" ); document.write( "2a - 24 = 80 - 2b \n" ); document.write( "2a + 2b = 80 + 24 \n" ); document.write( "2a + 2b = 104 \n" ); document.write( "Simplify, divide by 2 \n" ); document.write( "a + b = 52 \n" ); document.write( ": \n" ); document.write( "thrice the first number divided by 5 is equal to the second number divided by 4. \n" ); document.write( " \n" ); document.write( "cross multiply \n" ); document.write( "4(3a) = 5b \n" ); document.write( "12a = 5b \n" ); document.write( "12a - 5b = 0 \n" ); document.write( " 5a + 5b = 260 multiplied the 1st equation by 5 \n" ); document.write( "-------------- addition eliminates b, find a \n" ); document.write( "17a = 260 \n" ); document.write( "a ~ 15.294, I would have expected integers here, anyway \n" ); document.write( ": \n" ); document.write( "a + b = 52 \n" ); document.write( "15.294 + b = 52 \n" ); document.write( "b = 52 - 15.294 \n" ); document.write( "b = 36.706 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that satisfies the 2nd statement, using a calc: \n" ); document.write( " \n" ); document.write( "9.1764 ~ 9.1765, close anyway\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |