document.write( "Question 669667: solve p^2+p+4=0 \n" ); document.write( "
Algebra.Com's Answer #416503 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Use the quadratic formula to solve for p\r
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\n" ); document.write( "\n" ); document.write( "\"p+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"p+=+%28-%281%29%2B-sqrt%28%281%29%5E2-4%281%29%284%29%29%29%2F%282%281%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"p+=+%28-1%2B-sqrt%281-%2816%29%29%29%2F%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"p+=+%28-1%2B-sqrt%28-15%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"p+=+%28-1%2Bsqrt%28-15%29%29%2F2\" or \"p+=+%28-1-sqrt%28-15%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"p+=+%28-1%2Bi%2Asqrt%2815%29%29%2F2\" or \"p+=+%28-1-i%2Asqrt%2815%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Note: if you have NOT learned about complex/imaginary numbers yet, then you will simply say that there are no real solutions.
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