document.write( "Question 669481: a man travels a total distance of 166km/hr. his average speed for the first 130km is xkm/hr and for the remaining journey , (x-25)km/hr. if the whole journey takes 3 hours and 15 minutes , form an equation in terms of x.
\n" ); document.write( "solve this equation and hence find the time he would have saved if he maintains an average speed of xkm/hr throughout ?
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Algebra.Com's Answer #416490 by ankor@dixie-net.com(22740)\"\" \"About 
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a man travels a total distance of 166km/hr.
\n" ); document.write( " his average speed for the first 130km is xkm/hr and for the remaining journey, (x-25)km/hr.
\n" ); document.write( "if the whole journey takes 3 hours and 15 minutes, form an equation in terms of x.
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\n" ); document.write( "Change 3 hrs 15 min to 3.25 hrs
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\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( "\"130%2Fx\" + \"36%2F%28%28x-25%29%29\" = 3.25
\n" ); document.write( "Multiply by x(x-25), results
\n" ); document.write( "130(x-25) + 36x = 3.25x(x-25)
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\n" ); document.write( "130x - 3250 + 36x = 3.25x^2 - 81.25x
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\n" ); document.write( "166x - 3250 = 3.25x^2 - 81.25x
\n" ); document.write( "A quadratic equation
\n" ); document.write( "3.25x^2 - 81.25x - 166x + 3250 = 0
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\n" ); document.write( "3.25x^2 - 247.25x + 3250 = 0
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\n" ); document.write( "solve this equation
\n" ); document.write( "Use the quadratic formula to find x;
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( " a=3.25, b=-247.25, c=3250
\n" ); document.write( "\"x+=+%28-%28-247.25%29+%2B-+sqrt%28-247.25%5E2-4%2A3.25%2A3250+%29%29%2F%282%2A3.25%29+\"
\n" ); document.write( "Do this rather tedious math, the reasonable solution x ~ 59.18 km/h
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\n" ); document.write( "find the time he would have saved if he maintains an average speed of xkm/hr throughout ?
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\n" ); document.write( "\"166%2F59.18\" = 2.8 hrs
\n" ); document.write( "3.25 - 2.8 = .45 hrs saved (.45*60 = 27 min)
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