document.write( "Question 669481: a man travels a total distance of 166km/hr. his average speed for the first 130km is xkm/hr and for the remaining journey , (x-25)km/hr. if the whole journey takes 3 hours and 15 minutes , form an equation in terms of x.
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document.write( "solve this equation and hence find the time he would have saved if he maintains an average speed of xkm/hr throughout ? \n" );
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Algebra.Com's Answer #416490 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a man travels a total distance of 166km/hr. \n" ); document.write( " his average speed for the first 130km is xkm/hr and for the remaining journey, (x-25)km/hr. \n" ); document.write( "if the whole journey takes 3 hours and 15 minutes, form an equation in terms of x. \n" ); document.write( ": \n" ); document.write( "Change 3 hrs 15 min to 3.25 hrs \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( " \n" ); document.write( "Multiply by x(x-25), results \n" ); document.write( "130(x-25) + 36x = 3.25x(x-25) \n" ); document.write( ": \n" ); document.write( "130x - 3250 + 36x = 3.25x^2 - 81.25x \n" ); document.write( ": \n" ); document.write( "166x - 3250 = 3.25x^2 - 81.25x \n" ); document.write( "A quadratic equation \n" ); document.write( "3.25x^2 - 81.25x - 166x + 3250 = 0 \n" ); document.write( ": \n" ); document.write( "3.25x^2 - 247.25x + 3250 = 0 \n" ); document.write( ": \n" ); document.write( "solve this equation \n" ); document.write( "Use the quadratic formula to find x; \n" ); document.write( " \n" ); document.write( " a=3.25, b=-247.25, c=3250 \n" ); document.write( " \n" ); document.write( "Do this rather tedious math, the reasonable solution x ~ 59.18 km/h \n" ); document.write( "; \n" ); document.write( "find the time he would have saved if he maintains an average speed of xkm/hr throughout ? \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "3.25 - 2.8 = .45 hrs saved (.45*60 = 27 min) \n" ); document.write( " |