document.write( "Question 60672This question is from textbook Essential Algebra
\n" ); document.write( ": Hi I am having a problem grasping consecutive integers. I do not know how to write out this equation. Any help would be appreciated.
\n" ); document.write( "Thanks,
\n" ); document.write( "Lee Ann\r
\n" ); document.write( "\n" ); document.write( "Problem: Twice the sum of the first and third of three consecutive integers is fifteen less than the second integer. Find the integers.
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Algebra.Com's Answer #41648 by uma(370)\"\" \"About 
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Cosecutive integers are numbers which follow each other.
\n" ); document.write( "For example: 2, 3, 4, 5...are consecutive.
\n" ); document.write( "Similarly 39, 38, 37, 36, 35,.... are consecutive.
\n" ); document.write( "It follows that the integers have a difference of 1.
\n" ); document.write( "So let us take the 3 consecutive integers as (x-1), x,(x+1)\r
\n" ); document.write( "\n" ); document.write( "Twice the sum of the first and the third integers is
\n" ); document.write( "2[(x-1) + (x+1)]\r
\n" ); document.write( "\n" ); document.write( "This is 15 less than the second integer.
\n" ); document.write( "==> 2[(x-1) + (x+1)] = x - 15\r
\n" ); document.write( "\n" ); document.write( "==> 2(x-1+x+1) = x - 15
\n" ); document.write( "==> 2(2x) = x - 15
\n" ); document.write( "==> 4x = x - 15
\n" ); document.write( "==> 4x - x = -15
\n" ); document.write( "==> 3x = -15
\n" ); document.write( "==> 3x/3 = -15/3
\n" ); document.write( "==> x = -5
\n" ); document.write( "So the first integer is x - 1 = -5 -1
\n" ); document.write( " = -6\r
\n" ); document.write( "\n" ); document.write( "The second integer = x
\n" ); document.write( " = -5\r
\n" ); document.write( "\n" ); document.write( "The third integer = x+1
\n" ); document.write( " = -5 + 1
\n" ); document.write( " = - 4\r
\n" ); document.write( "\n" ); document.write( "The three consecutive integers are -6, -5, -4.\r
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\n" ); document.write( "\n" ); document.write( "Good Luck!!!
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