document.write( "Question 669620: If you deposit $1000 in an account that pays 6% annual interest commpounded continuously, what will the balance be after five years? \n" ); document.write( "
Algebra.Com's Answer #416464 by jim_thompson5910(35256)\"\" \"About 
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\"A=Pe%5E%28rt%29\" Start with the continuous compounding formula.\r
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\n" ); document.write( "\n" ); document.write( "\"A=1000%2Ae%5E%280.06%2A5%29\" Plug in \"P=1000\", \"r=0.06\" (the decimal equivalent of 6%), and \"t=5\".\r
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\n" ); document.write( "\n" ); document.write( "\"A=1000%2Ae%5E%280.3%29\" Multiply \"0.06\" and \"5\" to get \"0.3\".\r
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\n" ); document.write( "\n" ); document.write( "\"A=1000%2A1.349858807576\" Raise 'e' (which is approximately 2.71828) to the power \"0.3\" to get \"1.349858807576\" (this value is approximate).\r
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\n" ); document.write( "\n" ); document.write( "\"A=1349.858807576\" Multiply \"1000\" and \"1.349858807576\" to get \"1349.858807576\".\r
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\n" ); document.write( "\n" ); document.write( "\"A=1349.86\" Round to the nearest hundredth (ie to the nearest penny).\r
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\n" ); document.write( "\n" ); document.write( "The balance after five years is $1349.86
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